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Article #1100Re: Can Anyone Help? MS Access '97
From: Asif A. Kazi
Date: Fri, 20 Nov 1998 00:00
Date: Fri, 20 Nov 1998 00:00
29 lines
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1566 bytes
Use function LEFT() which: Extract part of existing text values using a calculated field 1 In query Design view, create a query. Add the tables whose records you want to use. 2 To find values in part of a field, use the Left, Right, or Mid function in an expression in an empty cell in the Field row in the query design grid. The syntax for these functions is: Left(stringexpr,n) Right(stringexpr,n) Mid(stringexpr,start,n) The stringexpr argument can be either a field name (enclosed in brackets) or a text expression; n is the number of characters you want to extract; start is the position of the first character you want to extract. The following table shows examples of these functions. If the value in Part ID is This expression Returns BA-7893-R12 Left([PartID],2) BA BA-7893-R12 Right([PartID],3) R12 BA-7893-R12 Mid([PartID],4,4) 7893 reards asif
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X-Google-Language: ENGLISH,ASCII-7-bit X-Google-Thread: 10f2ee,1dad23c459da5f08 X-Google-Attributes: gid10f2ee,public From: "Asif A. Kazi" <asif@szabist.edu.pk> Subject: Re: Can Anyone Help? MS Access '97 Date: 1998/11/20 Message-ID: <36548de2.0@news3.ibm.net> X-Deja-AN: 413637471 References: <3638fba6.0@news.albatross.co.uk> X-Notice: should be reported to postmaster@ibm.net X-MimeOLE: Produced By Microsoft MimeOLE V4.72.3110.3 X-Complaints-To: postmaster@ibm.net X-Trace: 19 Nov 1998 21:30:10 GMT, 139.92.118.153 Organization: IBM.NET Newsgroups: ab.software.developers