🚀 go-pugleaf

Roy,

It's indeed confusing that there are two types of search, as Dirk points out. So this would work:

myText = app.selection[0].parentStory;
app.myfindPreferences = null;
app.mychangePreferences = null;
myPound = myText("�")

Now myPound is a collection (or array). Your next section doesn't do what you expect because you now do a search on a string (your "myString" is a string), but what you want is to search just one line (that's I suppose what the for-loop is for). .indexOf, by the way, takes just one argument, so you'd have to say

myResult = myString.indexOf("�")

which is the quivalent to

myResult = myString.search("�")

Anyway, myResult is a number, so you can't say myResult.parentLine: objects have parents, numbers and strings don't--quite apart from the fact that parentLine doesn't exist. But your problem is to get a reference to the line in which you found the pound symbol. A bit counter-intuitively, an object of type character has a property Lines, which is a collection with just one item in it, namely, the line in which that character occurs. So myPound[i].lines[0] is the line in which myPounds[i] occurs. So your for-loop could look like this:

for( i=0 ; i < myPound.length ; i++ )
  {
  myTab = myPound[i].lines[0].search( "*^t" );
  if( myTab.length > 0 )
    myPound[i].lines[0].appliedParagraphStyle = "Goerge Kidner body text";
  }

Peter