🚀 go-pugleaf

Nige wrote:
> @Cells^[0]
> 
> whats do the @ and the ^ and the [0] indicate.

The whole thing gives you the address of (@) the fist item ([0]) of the 
memory that cells uses (^). Read some tutorials on pointers.

Cheers,
Nicholas Sherlock

Nige wrote:
> Looking at some sample code.
> 
> I have a line, which calls a function
> 
> and the 3rd parameter is  @Cells^[0]
> 
> whats do the @ and the ^ and the [0] indicate.
> 
> thanks
> 
> 
  The @ generates an address of an item.
  so lets break this down.

  Cells is being treated like a pointer and
thus the use of ^ meaning that you are
fetching data via the pointer which is like
a road map giving directions of where the
start of the data which makes up the object
"CELLS" resides in.
    Since it's obvious that Cells must not
be a pointer already to start with, using the
@ infront will generate a pointer address of that
object.
    and the use of the [0] is like any other
array from that point on.
  it will simply use the Pointer address as the
starting base with the an offset of what
ever in the [?] to calculate the distant to
move from the start of the pointer.



-- 
Real Programmers Do things like this.
http://webpages.charter.net/jamie_5

"Nige" <nkarnold@blueyonder.co.uk> wrote in message 
news:Ihplf.160032$Es4.143191@fe2.news.blueyonder.co.uk...
> Looking at some sample code.
>
> I have a line, which calls a function
>
> and the 3rd parameter is  @Cells^[0]
>
> whats do the @ and the ^ and the [0] indicate.

The code won't compile. In any case it is nonsensical. @Cells and Cells 
mean the same thing as does Cells^ and Cells, presuming Cells is the name 
of an array.

Nige wrote:
> Looking at some sample code.
> 
> I have a line, which calls a function
> 
> and the 3rd parameter is  @Cells^[0]
> 
> whats do the @ and the ^ and the [0] indicate.
> 
> thanks
> 
> 
@ = adress of
^ dereferences a pointer
[x] is the x'th position in a list or array.