🚀 go-pugleaf

In article <01bd9f1d$19766760$8c2e63c3@default>,
  "Reg Edwards" <g4fgq.regp@btinternet.com> wrote:
>
> Its quite simple really.
>
> A complex number is of the form x + jy where j is the squareroot of minus
> 1.
>
> Don't let j put you off because you will never have to work out what it is.
> All you have to do is square it.
>
> So j squared is minus 1.
>
> It now becomes easy to multiply two complex numbers together as follows -
>
> (a + jb)*(c + jd)  =  ac - bd + j(bc + ad) which is just another complex
> number.
>
> Think of j as a radioactive tracer which allows the "imaginary" components
> to be kept track of in the course of a long calculation.
>
> And thats all there is to it - well almost. But it's all very easy.

I don't know about it all being very easy, but here's the other standard
results you need: (a + jb)+(c + jd)  = (a+c)+j(b+d) (a + jb)/(c + jd) 
=(a+jb)*(c-jd)/(cc+dd)

mod(a+jb)=sqrt(aa+bb)
theta(a+jb)=atan(b/a)  ....(but get the right quadrant)

a+jb=mod(a+jb)*exp(j.theta)

Their great advantage is that in exponential form (the last equation) you can
manipulate 2 dimensional numbers in one expression.

On a graph, you plot the real part on the x axis and the imaginary part on
the y axis.





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