🚀 go-pugleaf

Hi,

I didn't scan through the complete example but what makes me curious is
this:

strcpy(s[0].id, "1000001");

This will copy 8 characters (the 8'th char is the delimiting 0) to the
target.
BUT your target can hold only 7 chars. I expect this will overwrite the
next item in your struct. And subsequently trash something.

Roland


"EL" <lameddie@yahoo.com> wrote in message
news:a2um2g$1q1@imsp212.netvigator.com...
> Hi all,
>
> I want to pass a structure to my own function and change its value,
however
> i couldn't get the expected result. why?
>
> struct mystr
> {
> char id[7], name[21];
> };
>
> void appRec(mystr* , int&);
>
> void main()
> {
>   mystr s[50];
>   int i, j, b, ttl;
>   char vid[7], bid[7];
>
>   strcpy(s[0].id, "1000001");
>   strcpy(s[0].name, "RobertHi");
>   strcpy(s[1].id, "1000008");
>   strcpy(s[1].name, "KawaiiNic");
>
>   ttl = 2;
>   appRec(s, ttl);
>   for (i=0; i<ttl ; i++)
>   {
>    cout << "\nStud ID : " << s[i].id;
>    cout << "\tName    : " << s[i].name;
>   }
>
> }
>
> void appRec(mystr *s1, int &ttl)
> {
>   ttl++;
>   cout << "\nTotal in function: " << ttl;
>   strcpy(s1[ttl].id, "1000005");
>   strcpy(s1[ttl].name, "Minotaic");
>   int i=0;
>   for (i=0; i<ttl; i++)
>   {
>    cout << "\nStud ID fnt : " << s1[i].id;
>    cout << "\tName    fnt : " << s1[i].name;
>   }
> }
>
>