🚀 go-pugleaf

On Fri, 14 Jul 2000 20:58:49 GMT, "kristofer stenberg"
<kristofer.stenberg@chello.se> wrote:

> Say I have an object Dog and a method Dog::run().
> ptr is a pointer to Dog and funcPtr is pointer to run(). First I try to call
> run() with (ptr ->*   funcPtr) () and it works fine. Then I try (ptr ->
> *funcPtr) ()
> and its an error. A space between -> and * shouldnt make a difference,
> should it?

Yes, it should. The token defining the pointer calls of member
functions are

	->*   .*

with no spaces between them. Them same as  ++ is the increment
operator and << is the shift left operator.


		i+ +;
		i< <1;

don't work.


Regards
Horst