🚀 go-pugleaf

Where's the problem?
You have a redefinition int x and float x, which doesn't work
You can just compare with:
int x = 20;
float y =20.0;
if(x==y)
    printf("Equal!");
else
    printf ("Not equal!");

That's all. You can also cast (converting diffrent types):
y = (float)x;

"Alya Al Omrani" <alomrani@emirates.net.ae> schrieb im Newsbeitrag
news:9iejot$4an2@news.emirates.net.ae...
> Hi, how can i check if a floating point value is equal to integer value ?
> I tried looking of there is a function that does so but there isn't
>
> I tried doing the following
>
> /* lets say those are my values */
> int x=20;
> float x=20.0, z;
>
> z=(float)x;
> /* I used a printf staetment to check that the value of x was assigned to
z
> and it worked ! */
> printf("%f", z);
>
> /* here i want to check */
> if(z==x)                      /* at this instant it freezes */
>     printf("values are equal");
> else
>     printf("they r not euqal");
> ///////////////
>
>
> I sthere a substitue method that i can do so, i tried taking the % modulus
> of both z and x to see if it will give zero but i got same erro, the
program
> wont compile
>
>
>

> if(z==(float)x)

Er, would this not mess things up?  Floating the int *could* move off to
nearest float (your 20 could become 19.999999999, etc) and that may or may
not be == to z.  Depending on what you want, you may want to be more
precise:

const float tol = 0.00001;
float f, chek;
int i;
f = i = 20;
chek = fabs(f-i);
if(chek < tol) //then they are more or less equal. Tol could be the smallest
representable float, but I would use 10 times this or more.
  etc....

I don't think this is an issue for small integers; it may not be an issue at
all, not sure.

Alya Al Omrani wrote:
> 
> Hi, how can i check if a floating point value is equal to integer value ?
> I tried looking of there is a function that does so but there isn't
> 
> I tried doing the following
> 
> /* lets say those are my values */
> int x=20;
> float x=20.0, z;
> 
> z=(float)x;
> /* I used a printf staetment to check that the value of x was assigned to z
> and it worked ! */
> printf("%f", z);
> 
> /* here i want to check */
> if(z==x)                      /* at this instant it freezes */
>     printf("values are equal");
> else
>     printf("they r not euqal");
> ///////////////
> 
> I sthere a substitue method that i can do so, i tried taking the % modulus
> of both z and x to see if it will give zero but i got same erro, the program
> wont compile

Are you getting an error since you are defining x twice:

> int x=20;
> float x=20.0, z;

You can cast the comparison:

int x=20;
float z=20.0;
...
if(z==(float)x)

Hi I think it would be no problem if you convert float to integer
instead of interger to float just for comparision purpose

instead of (float(x) == y) 
to (x == (int) y)

this will never fail.

Sanjay 

"Alya Al Omrani" <alomrani@emirates.net.ae> wrote in message news:<9iejot$4an2@news.emirates.net.ae>...
> Hi, how can i check if a floating point value is equal to integer value ?
> I tried looking of there is a function that does so but there isn't
> 
> I tried doing the following
> 
> /* lets say those are my values */
> int x=20;
> float x=20.0, z;
> 
> z=(float)x;
> /* I used a printf staetment to check that the value of x was assigned to z
> and it worked ! */
> printf("%f", z);
> 
> /* here i want to check */
> if(z==x)                      /* at this instant it freezes */
>     printf("values are equal");
> else
>     printf("they r not euqal");
> ///////////////
> 
> 
> I sthere a substitue method that i can do so, i tried taking the % modulus
> of both z and x to see if it will give zero but i got same erro, the program
> wont compile

On Tue, 10 Jul 2001 14:01:37 +0300, "Alya Al Omrani"
<alomrani@emirates.net.ae> wrote:

>Hi, how can i check if a floating point value is equal to integer value ?
>I tried looking of there is a function that does so but there isn't

[snip code with problems]

Your question might mean one of two things:

(a) Is a particular floating point value, call it x, actually an
integer expressed in floating point form?

(b) Is a particular floating point value x equal to some integer y?

If we can answer (a) then it is trivial to answer (b).  Let us suppose
we have two functions, float and int.  Then, provided that x is in
normal form, then x is an integer in floating point form if
	x .bweq. float(int(x))
where .bweq. denotes bitwise equality, i.e., x and float(int(x)) have
the same bit pattern.

 
Richard Harter, cri@tiac.net,
http://www.tiac.net/users/cri, http://www.varinoma.com
It is unfortunate that the dishonest politicians give
the remaining one percent of their profession a bad name.

On 11 Jul 2001 00:37:31 -0700, san_2820@yahoo.com (Sanjay kumar)
wrote:

>Hi I think it would be no problem if you convert float to integer
>instead of interger to float just for comparision purpose
>
>instead of (float(x) == y) 
>to (x == (int) y)
>
>this will never fail.

What will happen if y is too large to fit in an int?
-- 
Michael M Rubenstein

you can't even use == or != to compare two floats

"Alya Al Omrani" <alomrani@emirates.net.ae> wrote in message
news:9iejot$4an2@news.emirates.net.ae...
> Hi, how can i check if a floating point value is equal to integer value ?
> I tried looking of there is a function that does so but there isn't
>
> I tried doing the following
>
> /* lets say those are my values */
> int x=20;
> float x=20.0, z;
>
> z=(float)x;
> /* I used a printf staetment to check that the value of x was assigned to
z
> and it worked ! */
> printf("%f", z);
>
> /* here i want to check */
> if(z==x)                      /* at this instant it freezes */
>     printf("values are equal");
> else
>     printf("they r not euqal");
> ///////////////
>
>
> I sthere a substitue method that i can do so, i tried taking the % modulus
> of both z and x to see if it will give zero but i got same erro, the
program
> wont compile
>
>
>

Samantha Fox wrote:
> 
> you can't even use == or != to compare two floats
> 

Oh, you can! But the results of that test are often surprising.

-- 
Karl Heinz Buchegger
kbuchegg@gascad.at