Re: How to expand variables from string?

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#11

From: FrenKy
Date: Sun, 28 Oct 2007 19:49

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CrispieCritter@gmail.com wrote:
> On Oct 17, 1:24 pm, Olivier Langlois <olangl...@sympatico.ca> wrote:
>> Hi,
>>
>> First, sorry if I am cross-posting this question. I am not sure to
>> understand the difference between the 2 newsgroups.
>>
>> My problem is that I have a shell variable containing a string
>> composed of variable names preceded with the expension operator ('$')
>> and I am fighting with the shell to find a way to make the expension.
>> Here is an example:
>>
>> var1='$HOME'
>> echo $var1
>>
>> will display $HOME but I would like to find a construction that would
>> allow me to print the $HOME value from the var1 variable.
>>
>> Thank you for your assistance,
>> Olivier Langloishttp://www.olivierlanglois.nethttp://blog.olivierlanglois.net
> 
> Don't enclose the variable with quotes. For example:
> 
> HOME="Some Random Text"
> TEST=$HOME
> echo $TEST
> 
> This would then print the text "Some Random Text" without quotes which
> is what you want ?
> 
> Glenn
> 
This solution has one problem:
  HOME="Some Random Text"
  TEST=$HOME
  HOME="Some Random Text"
  echo $TEST

I'd use Ralf's suggestion.

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From: FrenKy <frenky@foo.com>
Newsgroups: alt.comp.lang.shell.unix.bourne-bash,gnu.bash
Subject: Re: How to expand variables from string?
Date: Sun, 28 Oct 2007 20:49:40 +0100
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