🚀 go-pugleaf

A computer program could emulate this situation with picking two pseudo-random
numbers from 1 to 3.  Or some true random event could be used like quantum
mechanics or something else like a three sided coin or three sided die :) or
maybe a six sided die dividing integrally by two.

The first random number represents the number of the door that has the prize,
and the second is the contestant's choice.  Argue this point for amusement.
Play this with a friend or enemy.  This is where a bad assumption could come
into play.  Blah.  Blah.  Blah.


       1/3        2/3      Chance of Numbers Equal or Not Equal
        =         !=
     ------------------
C   |   L    |     W  |    Result: W-win, L-lose
NC  |   W    |     L  |
     ------------------
Changing/Not Changing your choice

Chance of Winning = (Chance winning changing + Chance winning when not changing)
                    ------------------------------------------------------------
                                               Total chances

                  =  ( 2/3 + 1/3 ) / ( 1/3 + 1/3 + 2/3 + 2/3 )

                  =  1/2         (This is what everyone argues)

Chance of Winning when changing =  Chance winning when change 
                                  -----------------------------
                                   Total Chances when changing

                                = (2/3) / ( 1/3 + 2/3 )

                                = 2/3

---Loyal Gordon Bassett II
These are my opinions and nobody elses except mine.
Have a good day.
Please respond if you have any ideas.  Does it sound like
a cool
idea or what?
Live well party on rock and roll.  Smith says hi.