🚀 go-pugleaf

Jeff Liebermann  <jeffl@comix.santa-cruz.ca.us> wrote:

>A bit of math on counting the number of wireless access points
>required to cover San Francisco.

>The original numbers:
>|  http://www.outlook4mobility.com/commentary2005/oct1205.htm

>The revised version:
>|  http://www.outlook4mobility.com/commentary2005/oct1305.htm

Lessee.  If the inter-access point spacing is D, then the
density is 1/D^2 per unit area.   If they are optimally
arrayed in a honeycomb fashion, the maximum distance to a 
client is D / (2 * cos(pi/6), or 0.57 * D.

If you want 300 feet to be the maximum distance to a client, then
D = 526 feet, which is pretty close to exactly 0.1 miles,
so yeah.  100 AP's per square mile.  The revised calculation
is correct.

But (a) 300 feet is too far for this all to work and (b) you
won't be able to optimally place them so you'll need more.
I'd say 200 per square mile if you want it not to choke,
or 10,000 access points in San Francisco.

Steve

Steve