Article View: alt.uu.math.misc
Article #113Re: circle problem
From: Jeffrey Newmiller
Date: Fri, 27 Sep 1996 00:00
Date: Fri, 27 Sep 1996 00:00
46 lines
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2134 bytes
Scott Phung (landmark@vcn.bc.ca) wrote: : Hi, i'm wondering about the following: : : Given the length of two parallel chords in a circle, and a distance : between them, is there a way to find the length of a middle : parallel chord, that is halfway between the first and second parallel : chord? [snip] : : rough diagram: : : ----------a----------- : | : | : x/2 : | : | : --------b-------- : | : | : x/2 : | : | : ------c------ : : remeber, b is contained inside the circle, as with a and c. : You can use any reasonable value for a, c, and x. line ac, extended, will bisect the circle. The endpoints of c, c1 and c2, lie on the circle. one endpoint of a, a1, lies on the circle as well. construct a line from c1 to a1, construct bisector of this line, and intersection of this bisector with ac will be the center of the circle C with radius C-a1. now is easy to find length of line b. : Thanks, : Scott -- --------------------------------------------------------------------------- Jeff Newmiller The ..... ..... Go Live... DCN:<jdnewmil@dcn.davis.ca.us> Basics: ##.#. ##.#. Live Go... Work:<JeffN@endecon.com> Live: OO#.. Dead: OO#.. Playing Research Engineer (Solar/Batteries O.O#. #.O#. with /Software/Embedded Controllers) .OO#. .OO#. rocks...3k ---------------------------------------------------------------------------
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X-Google-Language: ENGLISH,ASCII-7-bit X-Google-Thread: f7972,413d2dc7b281b447 X-Google-Attributes: gidf7972,public X-Google-Thread: 1077c2,413d2dc7b281b447 X-Google-Attributes: gid1077c2,public From: jdnewmil@wheel.dcn.davis.ca.us (Jeffrey Newmiller) Subject: Re: circle problem Date: 1996/09/27 Message-ID: <52g2is$7kb@mark.ucdavis.edu> X-Deja-AN: 185615718 references: <521bmd$376@milo.vcn.bc.ca> followup-to: alt.uu.math.misc,can.schoolnet.math.sr organization: Davis Community Network - Davis, California, USA newsgroups: alt.uu.math.misc,can.schoolnet.math.sr