🚀 go-pugleaf

On Sun, 27 Dec 1998 13:42:44 -0600, vmhjr@frii.com (Virgil Hancher)
wrote:

>In article <01be319a$e3091360$1cc8fcc1@default>, "GREGB" <greg_b@usa.net> wrote:
>
>> hi all,
>> my problem is X^2-5X+6 ?
>> 
>> Aline 12.
>> 
>> best regards.
>
>What about X^2-5X+6 ?
>
>X^2-5X+6, by itself, is not a problem.
>
>What is it that you want to do with X^2-5X+6?
>
>
>
>If you want to complete the square,
>   X^2-5X+6 =
>   (X^2 -2(5/2)X + 25/4 ) + 6 - 25/4 =
>   (X - 5/2)^2 - 1/4 =
>   (-5/2)^2 - (1/2)^2, difference of two squares.
>
>If you want to factor it, ( see the completion of the square above)
>   X^2-5X+6 = 
>   (X - 5/2 + 1/2)(X- 5/2 - 1/2) = 
>   (X - 2)(X - 3).
>
>
>If you want to solve X^2-5X+6 = 0, use the factorization above to get
>   x = 2 or x = 3
>
>If you want to apply the quadratic formula to X^2-5X+6 = 0,
>
>   sqrt((-5)^2 - 4(1)(6)) = sqrt(1) = 1
>
>   x = (-(-5)-1)/2 = 4/2 = 2
>or
>   x = (-(-5)+1)/3 = 6/2 = 3
>
>
>Or do you want to do something else?

In effect it is a strange question...
bah?
Giuseppe Vatinno
(Rome, Italy)