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Article #40

Re: problem

#40
From: Virgil Hancher
Date: Sun, 27 Dec 1998 00:00
42 lines
1967 bytes
In article <01be319a$e3091360$1cc8fcc1@default>, "GREGB" <greg_b@usa.net> wrote:

> hi all,
> my problem is X^2-5X+6 ?
> 
> Aline 12.
> 
> best regards.

What about X^2-5X+6 ?

X^2-5X+6, by itself, is not a problem.

What is it that you want to do with X^2-5X+6?



If you want to complete the square,
   X^2-5X+6 =
   (X^2 -2(5/2)X + 25/4 ) + 6 - 25/4 =
   (X - 5/2)^2 - 1/4 =
   (-5/2)^2 - (1/2)^2, difference of two squares.

If you want to factor it, ( see the completion of the square above)
   X^2-5X+6 = 
   (X - 5/2 + 1/2)(X- 5/2 - 1/2) = 
   (X - 2)(X - 3).


If you want to solve X^2-5X+6 = 0, use the factorization above to get
   x = 2 or x = 3

If you want to apply the quadratic formula to X^2-5X+6 = 0,

   sqrt((-5)^2 - 4(1)(6)) = sqrt(1) = 1

   x = (-(-5)-1)/2 = 4/2 = 2
or
   x = (-(-5)+1)/3 = 6/2 = 3


Or do you want to do something else?
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From: vmhjr@frii.com (Virgil Hancher)
Subject: Re: problem
Date: 1998/12/27
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