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Started by Enrico Talinucci
Fri, 28 Jan 2000 00:00
Bound for mixed partial derivatives
Author: Enrico Talinucci
Date: Fri, 28 Jan 2000 00:00
Date: Fri, 28 Jan 2000 00:00
43 lines
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2574 bytes
Hi everybody! I'm in trouble with the following problem. f: R^2 -> R is an infinitely differentiable function. I know an upper bound for the modulus of its pure partial derivatives, i.e. |d^n f/dx^n| and |d^n f/dy^n|, for every (x,y) \in R^2. I need to find a bound on its mixed p.d., d^(k+h) f /(dx^k dy^h). Now I'll detail the question. The data is: |d^k f/dx^k| < A_x ^k ||(x,y)|| |d^k f/dy^k| < A_y ^k ||(x,y)|| for every (x,y) and every k, where A_x, A_y are known constants and ||..|| is a norm on R^2, let's say the Euclidean norm. The inequalities holds for k=0 too. The target is finding a bound B(k, h, A_x, A_y) so that: |d^(k+h) f /(dx^k dy^h)| < B(k, h, A_x, A_y) ||(x,y)|| for every (x,y), k, h. An hypotesis could be: B = A_x^k A_y^h I couldn't prove it neither find a counterexample. It's just to give an idea of what I'm looking for. Does such a bound exist? If so, can you help me to find it? If not, can you give me a counterexample, i.e. a function who satisfies the given bounds, but for which at least one m.p.d. is unbounded with respect to ||(x,y)||? Thanks in advance for your help. Enrico Talinucci
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