🚀 go-pugleaf

Out-classed by a High Schooler!!!!
This is in prestandard C++, but you get the idea on how to do it.  This
works! I have compiled and executed it my self in Microsoft Visual Studio!
#include <iostream.h>
int main()

{
int a;
int counter=0;
int b;
int total=0;
cout<<"This program will multiply two integers(This number can be
negative!):"<<endl;
cout<<"Please enter first number:"<<endl;
cin>>a;
cout<<"Please enter second number(This number cannot be negative!):"<<endl;
cin>>b;
do
{
 total=total+a;
 counter++;
}while(counter<b);
cout<<total<<endl;
return 0;
}

CM <mckenzie992@comcast.net> wrote in message
news:EnGl9.19402$q42.1001817@bin3.nnrp.aus1.giganews.com...
> Hello all,
> I have what I am sure most of you will find an extremely easy program to
> write.  It is to simply multiply two numbers together without using '*'
So,
> two numbers, X times Y - X+X+X .. Y times.  I imagine a for loop is needed
> but I can not figure out how to write it and - also have searched for a
few
> hours for clues on how to.  Below is what I have so far, don't laugh, I
have
> to start somewhere!!  But nonetheless, I have to get rid of the expression
> c=a*b and get a loop in there ... Can anyone help me?
>
>
> #include <iostream>
> using namespace std;
> int main()
>
> {
>  double a;
>  double c;
>  double b;
>  cout << "This program will multiply two integers:" <<endl;
>  cout << "Please enter first number:" <<endl;
>  cin >> a;
>   cout << "Please enter second number:"<<endl;
>  cin >> b;
>
>   c=a*b;
>
>
> cout <<"The answer is " << c <<endl;
>
>
>
> }

It would have been better for you to at least
try to write the loop and post it here, no matter
how 'wrong' you might believe it is.

Here's one of several possiblities.
(Don't just turn it in, though, be prepared
 to explain to your instructor *why* it works. :-) )

int mult(int a, int b)
{
    int result(0);

    while(a--)
        result += b;

    return result;
}

Any questions, just ask.

HTH,
-Mike