🚀 go-pugleaf

try this:

String bb;

int xx = 2;

bb = String.valueOf(xx);

this will give the value of the xx var as a String object...

--this valueOf(int x) method is static so you don't need to instantiate a
String object to utilize it...

or, if you're trying to convert an int to a String, just use this:

Integer xx = new Integer(2);

xx.toString();

best.

kelbarnes.

"Paul Murray" <pmurray@nospam.bigpond.com> wrote in message
news:NEYR6.31881$hV3.53039@newsfeeds.bigpond.com...
> See java.text.ChoiceFormat .
>
> --
> --------------------------------------------------------------
> Sometimes he answers "Yes", sometimes "No", sometimes "Wait", and
sometimes
> he gives you something different.
> You get the same set of responses praying to a rock.
> http://www.users.bigpond.com/pmurray
> ICQ: 26066755
>
> "rastgoo" <rastgoo@thefreeinternet.co.uk.NOSPAM> wrote in message
> news:3b16b1bd_3@news.bizonline.net...
> >
> > Luke Vanderfluit <luke@chipcity.com.au> wrote in message
> > news:3A63FC90.3C832EFA@chipcity.com.au...
> > > Hi
> > >
> > > I need help with this.
> > > Why doesn't the following code work?:
> > > I need to interpret a line of text as an integer.
> > >
> > > String a = "yes";
> > > String b = "ls";
> > > int aa = Integer.valueOf("foo").intValue();
> > > int bb = Integer.valueOf("bar").intValue();
> > > System.out.println(aa);
> > > System.out.println(bb);
> > >
> > > This throws a NumberFormatException
> > >
> > > How can I read a String as an Integer
> > >
> > > Can you help me please.
> > >
> > > Desperate,
> > > --
> > >   Luke Vanderfluit
> > >
> > >   Phone 61 8 8556 6112
> > >
> > >   Aldinga Beach, South Australia
> > >
> > >
> > >
> >
> >
>
>