n^0 = 1

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3 total messages Started by DonH Sun, 08 Apr 2012 19:08

#862

Author: DonH
Date: Sun, 08 Apr 2012 19:08

10 lines
1673 bytes

Yes, take any number (n) and raise it (^) to the power zero (0) and you get 
one(1).
    2^2 = 4; 2^1 = 2; and so (by analogy?), 2^0 = 1.
  I've yet to see proof of this, as distinct from dogmatic assertion.
    2^? = 0  or is this an absurdity?  As zero is always just zero?
    2^-1 =  1/2. (ie 0.5) and,
    2^1/2 = square root of 2, ie. 1.414
 So, 2^0 = 1. (Two multiplied by itself zero times gives one?  Or two, or 
zero?)
    3^0 = 1;  4^0 = 1; 5^0 = 1.....

Re: n^0 = 1

#864

Author: DonH
Date: Thu, 19 Apr 2012 19:57

20 lines
1989 bytes

"DonH" <donlhumphries@bigpond.com> wrote in message 
news:Xmlgr.5518$%E2.4315@viwinnwfe01.internal.bigpond.com...
> Yes, take any number (n) and raise it (^) to the power zero (0) and you 
> get one(1).
>    2^2 = 4; 2^1 = 2; and so (by analogy?), 2^0 = 1.
>  I've yet to see proof of this, as distinct from dogmatic assertion.
>    2^? = 0  or is this an absurdity?  As zero is always just zero?
>    2^-1 =  1/2. (ie 0.5) and,
>    2^1/2 = square root of 2, ie. 1.414
> So, 2^0 = 1. (Two multiplied by itself zero times gives one?  Or two, or 
> zero?)
>    3^0 = 1;  4^0 = 1; 5^0 = 1.....
>

# Some more Zeroics:
(1) 5^0 - 7^0 = 0
(2) 5^0 + 7^0 = 2
(3) 5^0 * 7^0 = 1
(4) 1^0 = 1^1
(5) 2^0 / 2^1 = 0.5

Re: n^0 = 1

#865

Author: DonH
Date: Fri, 20 Apr 2012 21:14

15 lines
1898 bytes

"DonH" <donlhumphries@bigpond.com> wrote in message 
news:Xmlgr.5518$%E2.4315@viwinnwfe01.internal.bigpond.com...
> Yes, take any number (n) and raise it (^) to the power zero (0) and you 
> get one(1).
>    2^2 = 4; 2^1 = 2; and so (by analogy?), 2^0 = 1.
>  I've yet to see proof of this, as distinct from dogmatic assertion.
>    2^? = 0  or is this an absurdity?  As zero is always just zero?
>    2^-1 =  1/2. (ie 0.5) and,
>    2^1/2 = square root of 2, ie. 1.414
> So, 2^0 = 1. (Two multiplied by itself zero times gives one?  Or two, or 
> zero?)
>    3^0 = 1;  4^0 = 1; 5^0 = 1.....
>

# ...and 0^0 = 1.

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