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2 total messages Started by amukhtar Sat, 23 Nov 1996 00:00
help me on this problem please!
#70
Author: amukhtar
Date: Sat, 23 Nov 1996 00:00
10 lines
629 bytes
If someone can help me on this problem, I really appreciated.....

Y = ( 19x - 12 ) / (5x^2 - 15x)

I need you to solve for x...
for example
Y  = 3x then x = y/3
thank you again
amukhtar@mail.bcpl.lib.md.us
Re: help me on this problem please!
#72
Author: Matthew Johnson
Date: Tue, 26 Nov 1996 00:00
30 lines
1150 bytes
<amukhtar@mail.bcpl.lib.md.us> writes:

>If someone can help me on this problem, I really appreciated.....

>Y = ( 19x - 12 ) / (5x^2 - 15x)

>I need you to solve for x...
>for example
>Y  = 3x then x = y/3
>thank you again
>amukhtar@mail.bcpl.lib.md.us

To which I reply:
There is only one answer possible, but I am not sure this is
really what you want.  The answer is

x = (15Y + sqrt( (15Y)^2 -240Y ) ) / 10Y

for the more positive root, and

x = (15Y + sqrt( (15Y)^2 -240Y ) ) / 10Y

Of course, depending on your value for Y, the answers might
be complex numbers.


Matthew Johnson
Sabaki Engineering
mejohnsn@netcom.com
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