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Started by amukhtar
Sat, 23 Nov 1996 00:00
help me on this problem please!
Author: amukhtar
Date: Sat, 23 Nov 1996 00:00
Date: Sat, 23 Nov 1996 00:00
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If someone can help me on this problem, I really appreciated..... Y = ( 19x - 12 ) / (5x^2 - 15x) I need you to solve for x... for example Y = 3x then x = y/3 thank you again amukhtar@mail.bcpl.lib.md.us
Re: help me on this problem please!
Author: Matthew Johnson
Date: Tue, 26 Nov 1996 00:00
Date: Tue, 26 Nov 1996 00:00
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<amukhtar@mail.bcpl.lib.md.us> writes: >If someone can help me on this problem, I really appreciated..... >Y = ( 19x - 12 ) / (5x^2 - 15x) >I need you to solve for x... >for example >Y = 3x then x = y/3 >thank you again >amukhtar@mail.bcpl.lib.md.us To which I reply: There is only one answer possible, but I am not sure this is really what you want. The answer is x = (15Y + sqrt( (15Y)^2 -240Y ) ) / 10Y for the more positive root, and x = (15Y + sqrt( (15Y)^2 -240Y ) ) / 10Y Of course, depending on your value for Y, the answers might be complex numbers. Matthew Johnson Sabaki Engineering mejohnsn@netcom.com
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