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Article #1899

Re: Perl

#1899
From: Philip Paeps
Date: Wed, 03 Nov 2004 09:57
23 lines
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Nitro <nitroglycerine@skynet.be> wrote:
> Hoe kan ik in perl \r\n achter een string uithalen?

m/\r\n$/m?

> Ik heb dit geprobeerd met een regular expression, maar dit blijkt niet zo
> goed te gaan.
> 
> my $test = $in =~ m/(.*)\\r\\n/;

Waarom \\r\\n?

> Dit zou toch alles voor de \r\n moeten teruggeven?

Sure.  Maar is het niet makkelijker om gewoon je string te choppen?

 - Philip

-- 
Philip Paeps                              Please don't email any replies
philip@paeps.cx                               I follow the newsgroup.

  The sun goes down just when you need it the most.
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From: Philip Paeps <philip+usenet@paeps.cx>
Subject: Re: Perl
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