🚀 go-pugleaf

RetroBBS NetNews Server

Inspired by RockSolid Light RIP Retro Guy

Article View: bit.listserv.physhare
Article #1071

Re: Stopping and Starting!

#1071
From: John Mallinckrodt
Date: Fri, 23 Sep 1994 17:02
24 lines
1552 bytes
>         I am in dire need of some (perhaps obscure) information. I need
> to know roughly how long it takes an automobile to stop at a stop sign
> from 40mph. I need to know the time of the stop as well as the dist. over
> which the negative acceleration took place.

No problem (and certainly not obscure)

A typical rapid, but nonpanic, deceleration might be half a "g."
Since 1 "g" = 22 mph/s this means the car will lose about 10 mph
every second.  So, want to stop from 40 mph?  Then give yourself
4 seconds,  ... from 60 mph?  ... 6 seconds, etc.

For the distance, just use average velocity times the time to stop
where the average velocity is half the initial velocity.  So,
for example

distance stopping from 40 mph = 20 mph x (4/3600) h = 1/45 mile
                                                    = 120 ft

Hope this helps.

John Mallinckrodt
Cal Poly Pomona
ajmallinckro@csupomona.edu
Technical Details
Message-ID: <9409231702.AA05708@csupomona.edu>
Path: arc1-ca.pugleaf.net!bga.com!news.sprintlink.net!howland.reston.ans.net!paladin.american.edu!auvm!CSUPOMONA.EDU!ajmallinckro

Show Full Headers
Complete Article Headers
X-Google-Language: ENGLISH,ASCII-7-bit
X-Google-Thread: 16cfd8,56526ab2b11be590
X-Google-Attributes: gid16cfd8,public
X-Google-ArrivalTime: 1994-09-23 10:47:46 PST
Path: arc1-ca.pugleaf.net!bga.com!news.sprintlink.net!howland.reston.ans.net!paladin.american.edu!auvm!CSUPOMONA.EDU!ajmallinckro
Comments: Gated by NETNEWS@AUVM.AMERICAN.EDU
Newsgroups: bit.listserv.physhare
Message-ID: <9409231702.AA05708@csupomona.edu>
Date: Fri, 23 Sep 1994 10:02:48 PDT
Sender: Sharing resources for high school physics <PHYSHARE@PSUVM.PSU.EDU>
From: John Mallinckrodt <ajmallinckro@CSUPOMONA.EDU>
Subject: Re: Stopping and Starting!
Lines: 23