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Article #1071Re: Stopping and Starting!
From: John Mallinckrodt
Date: Fri, 23 Sep 1994 17:02
Date: Fri, 23 Sep 1994 17:02
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1552 bytes
> I am in dire need of some (perhaps obscure) information. I need
> to know roughly how long it takes an automobile to stop at a stop sign
> from 40mph. I need to know the time of the stop as well as the dist. over
> which the negative acceleration took place.
No problem (and certainly not obscure)
A typical rapid, but nonpanic, deceleration might be half a "g."
Since 1 "g" = 22 mph/s this means the car will lose about 10 mph
every second. So, want to stop from 40 mph? Then give yourself
4 seconds, ... from 60 mph? ... 6 seconds, etc.
For the distance, just use average velocity times the time to stop
where the average velocity is half the initial velocity. So,
for example
distance stopping from 40 mph = 20 mph x (4/3600) h = 1/45 mile
= 120 ft
Hope this helps.
John Mallinckrodt
Cal Poly Pomona
ajmallinckro@csupomona.edu
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X-Google-Language: ENGLISH,ASCII-7-bit X-Google-Thread: 16cfd8,56526ab2b11be590 X-Google-Attributes: gid16cfd8,public X-Google-ArrivalTime: 1994-09-23 10:47:46 PST Path: arc1-ca.pugleaf.net!bga.com!news.sprintlink.net!howland.reston.ans.net!paladin.american.edu!auvm!CSUPOMONA.EDU!ajmallinckro Comments: Gated by NETNEWS@AUVM.AMERICAN.EDU Newsgroups: bit.listserv.physhare Message-ID: <9409231702.AA05708@csupomona.edu> Date: Fri, 23 Sep 1994 10:02:48 PDT Sender: Sharing resources for high school physics <PHYSHARE@PSUVM.PSU.EDU> From: John Mallinckrodt <ajmallinckro@CSUPOMONA.EDU> Subject: Re: Stopping and Starting! Lines: 23