Re: ACTIVITY 12

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#872

From: Hasan Fakhruddin
Date: Mon, 12 Dec 1994 23:09

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For the diffraction experiment using the hair/wire what equation is applicable
to determine the width of the hair/wire?  Is it,

                        d sin(theta) = n (lambda)

where, d = width of the hair/wire
       theta = angular position of the nth dark fringe
        lambda = wavelength ?

If yes, then what is the justification for this equation?  Are you regarding
the edges of the obstacle as two sources as in the Young's double slit exp?

-Hasan Fakhruddin

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From: Hasan Fakhruddin <00h0fakhrudd@BSUVC.BSU.EDU>
Subject: Re: ACTIVITY 12
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