Re: Physics Questions

Thread View: bit.listserv.physhare

1 messages

[T] Back to Threads [V] Tree View [G] Group Articles

1 total messages Started by Darryl Steinert Fri, 12 May 1995 00:00

#67

Author: Darryl Steinert
Date: Fri, 12 May 1995 00:00

20 lines
1593 bytes

>2. The formula for calculating %error is
>        (measured value - accepted value)/ accepted value    x100%
>   They had to calculate the total torque on a mobile (made of wooden blocks
>   and fishing line). The total torque on each block should be zero for
>   it to be in equilibrium, BUT how do you calculate the %error when the
>   accepted value is zero?
>
>  The key to this is that you are actually making two sets of independent
measurements, the clockwise torques and the counter-clockwise torques.  When
comparing two independent measures of the same thing you calculate the
percent difference.  It is the difference divided by the sum times 100%.

               (|CWtorq. - CCWtorq|/(CWtorq. + CCWtorq.))*100%

Darryl L. Steinert
Dept of Physics               |voice mail: 812-866-7311
Hanover College               |fax: 812-866-7114
PO box 108                    |e-mail: steinert@alpha.hanover.edu
Hanover, IN 47243-0108   |"make it as simple as possible, but no more so"
USA

Thread Navigation

This is a paginated view of messages in the thread with full content displayed inline.

Messages are displayed in chronological order, with the original post highlighted in green.

Use pagination controls to navigate through all messages in large threads.

Back to All Threads