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Article #77arithmetic Robak 0,(9)+{1+}0=1 Time Theory
From: ksRobak
Date: Fri, 02 Jul 2004 16:06
Date: Fri, 02 Jul 2004 16:06
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2760 bytes
http://niusy.onet.pl/niusy.html?t=artykul&group=pl.sci.filozofia&aid=31516935
arithmetic Robak -- Time Theory
~~~~~~~~~~~~~~~~~~~~~~~~~
1
1/3=0, (10/3)
1 2
1/3=0, 3 (10/3)
1 2 3
1/3=0, 3 3 (10/3)
1 2 3 4
1/3=0, 3 3 3 (10/3)
1 2 3 4 5
1/3=0, 3 3 3 3 (10/3)
1 2 3 4 5 ... Re1 <== Re1 = N (max)
1/3=0, 3 3 3 3 3 ...(10/3)
n -> oo
1/3=3/10+3/10^2+3/10^3+...+3/10^(Re1-1)+(10/3)/10^Re1
1/3=0,(3)(10/3)
3*1/3=3*0,(3)(10/3)=0,(9)(30/3)=0,(9)(10)=1
1/Re1={1+}0=+0 <== +0 = PUNKT
Re1*{1+}0=1 ((~ oo*0=1 ))
A-A=0 <== 0 = (NC) = Arithmetic ZERO
PUNKT - (NC) =+0 - 0 = 1/Re1
__________________
1/3 +/- 3/10^n=3/10+...+(10/3)/10^Re1 +/- 3/10^n <== Re1=const
~~~~~~~~~~~~~~~~~~~~~~~~~~
PUNKT * a/b = +0 * a/b = {a/b+}0
~~~~~~~~~~~~~~~~~~~~~~~~~~
{a/b+}0 * Re1 = a/b
__________________
1. 1/3=3/10+(1/3)/10
2. 1/3=3/10+3/10^2 +(1/3)/10^2
3. 1/3=3/10+3/10^2 +3/10^3+(1/3)/10^3
n. 1/3=3/10+3/10^2 +3/10^3+...+3/10^n+(1/3)/10^n
Re1. 1/3=3/10+3/10^2 +3/10^3+...+3/10^Re1+(1/3)/10^Re1
=3/10+3/10^2 +3/10^3+...+(10/3)/10^Re1
0,(3)+(10/3)/10^Re1=0,(3)(10/3)=1/3
__________________
n N 1/N
1 1 1
2 2 1/2
3 3 1/3
4 4 1/4
5 5 1/5
...
Re1 Re1 +0
++++++++++++++++++ 1/N + 2/3
Re1+1 (NC) 2/3
Edward Robak - Krakow, 2.06.2004 - Poland
"ksRobak" ed_robak@wp.pl \|/ re:
--
Ipse dixit!
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From: "ksRobak" <ed_robak@interia.pl>
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Subject: arithmetic Robak 0,(9)+{1+}0=1 Time Theory
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