🚀 go-pugleaf

perfect!
this is exactly what I need!

Thanks
Josef



"Ed Mulroy [TeamB]" <dont_email_me@bitbuc.ket> schrieb im Newsbeitrag
news:473eec3e$1@newsgroups.borland.com...
> For FILE* style files you might try something like this:
>
> ----------------------
> #include <stdio.h>
>
> #ifdef __cplusplus
> using std::FILE;
> using std::_streams;
> #endif
>
> int NumFilesOpen()
>     {
>     FILE *fp = &_streams[0];
>     int num_open = 0;
>
>     for (int i = 0; i < _NFILE_; ++i, ++fp)
>         if (fp->fd != -1)
>             ++num_open;
>
>     return num_open;
>     }
> ----------------------
>
> Just remember that three files are going to be open at all times, stdin,
> stdout and stdprn.
>
> .  Ed
>
> > Josef Halder wrote in message
> > news:473eca61$1@newsgroups.borland.com...
> > Hi,
> >
> > is there a way to detect how many files are open at the moment?
> > My problem is when the program is running two weeks or longer without
> > restart then comes a point after that is not longer possible to open (to
> > read or to write) a file. After that point any attempt to open a file,
> > generates an error.
> > I belive there is a situation a file is not closed. But the program is
> > very
> > complex so it's difficult to find out.
> >
> > Example:
> > At various times during the program is running I open files with   FILE
*f
> > =
> > fopen("Filename.TXT","rt");
> > I read/write and after that I close with    fclose(f);
>
>