🚀 go-pugleaf

Maurice Anderson,

> What is char**.   I know char* is a pointer but what is the extra "*" for?
>

Same answer as before. 'char**' is a pointer to a pointer to a 'char'.

It's the low level way of describing an array of 'char *'. It's not needed 
often but it is needed when you want to store a pointer to an array of 'char 
*' eg:

  char * StringArray[ 500 ];
  
That's fine but if you need to just store a pointer to that array it becomes 
tricky. You can't just do:

  char * tempPtr[ 500 ]=StringArray;

Because that attempts to create another 500 element array and assign one to 
the other.

When declaring a function to take such an array you can do:

  void wibble( char * arg1[] );
  ...
  wibble( StringArray );

But you can't do that in actual code:

  char * tempPtr[]=StringArray;

Because then you are trying to create an array of unknown size and assign 
one to the other, doubly illegal.

The solution (suggested by the compiler error messages is):

  BYTE **srcBuffers=StringArray;

Always remember that '[]' is just a handy human readable alternative to 
pointer notation.
--
Andrue Cope
[Bicester, UK]