🚀 go-pugleaf

"nicolasr" <nicolasrNOSPAMATSIGNgmx.net> wrote in message
news:3e84fa8a@newsgroups.borland.com...

> Is
>    char buffer[MAX_PATH+2] = {0};
> equivalent to
>    char buffer[MAX_PATH+2] = ""; ?

{0} is a special-case shorthand that has an effect of zeroing out the entire
buffer's memory while initializing it.  I just tested both cases, and they
both zeroed out the entire buffer's memory, so I guess functionally they're
the same as far as the generated code from the compiler is concerned.  I
don't know what the C++ spec says the official rules are about initializing
fixed-sized character buffers with "", though.  I always prefer to use {0}
because it can be applied to structures as well, which "" can't be.

> I read up the strncpy() help. Is it here where the
> double \0 comes from?

Not in this particular situation, no.  strncpy() is simply a safer version
of strcpy() which allows you to specify the maximum number of characters to
copy, whereas strcpy() just copies until it reaches a null terminator
regardless of length.  By creating the buffer with 2 extra characters and
then stopping the maximum copying just prior to them, I'm letting the
buffer's initialization ensure that there will always be at least 2 null
terminators in the buffer regardless of how many characters are actually
copied into the buffer later.


Gambit


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