🚀 go-pugleaf

"smartdude80" <smartdude81@comcast.net> wrote in message
news:44a32f0c@newsgroups.borland.com...

> My program works with a specific file type and I just need to
> figure out how to get the file name of a file (belonging to my file
> class) when its being opened.  Hopefully i'll figure this out.

The filename will be passed to the application via its command line
parameters.  In the Registry, you have to specify the format of the command
line that is passed to the application, which %1 specifying where the
filename is to be placed, ie:

    c:\folder\myapp.exe "%1"

    c:\folder\myapp.exe "/openfile:%1"

    etc...

Using pure Win32 API coding, you can use the GetCommandLine() function, or
the lpCmdLine parameter of WinMain(), to get the command line.  If you are
using the VCL, you can alternatively use the GetParamCount() and
GetParamStr() functions.


Gambit