🚀 go-pugleaf

Look at ParamStr(0) or Application->ExeName.

Example:
   Path = ExtractFilePath( ParamStr(0) );
or:
   Path = ExtractFilePath( Application->ExeName );

-- 
Best regards,
Vladimir Stefanovic
"Marc" <bukwheat_NS@axess.com> wrote in message 
news:4266bf60@newsgroups.borland.com...
>
> Hi
>
> I am having an issue with retrieving the directory from where
> my application is started from, let me explain...
>
> GetModuleFileName and GetCurrentDirectory aren't cutting it for
> me.  GetMod... retruns the location of my exe as expected as
> for GetCurrentDirectory it works only when I am local on my
> system.
>
> Results from GetCurrentDirectory executions:
> My actual EXE resides on C:\program files\Somedirectory\Application.exe.
> 1. From the RUN dialog box GetCurrentDirectory return the location where 
> the EXE resides.
> 2. I have a batch file located on my desktop from which I
> execute the same command line as in the run command, in this
> case I get my desktop folder as expected.
> 3. Same batch file as the one on my desktop but this time I run
> it off a shared network path (\\somePC\SomeDirectory\file.bat
> in this case GetCurrectDirectory return C:\Windows.
>
> I have 2 questions, why C:\Windows and how can I have my
> application return the network path?
>
> Thanks for the help.
> Marc
>