🚀 go-pugleaf

Thank you for :
   sizeof( SomeStr ) / sizeof( SomeStr[0] )

Since I'm using the array combined with 'map' there's another problem. I'm 
trying to process a XML file. Although the array is static I want to keep 
it easy to be modified.
std::string	A_Attrib[]={"a0","a1","a2"};
std::string	B_Attrib[]={"b0"};

typedef	map< std::string, std::string*>	NodeType;
NodeType	Node;

// Initialize
Node["A"]= A_Attrib;
Node["B"]= B_Attrib;

i.e. when "A" comes in it will go through A_Attrib, B_Attrib for "B".
Unfortunately, sizeof doesn't work on Node["A"] because it's not an array 
of the elements which I want to count.

Now I have solved it by:
typedef	map< std::string, int>	NodeSizeType;

NodeSizeType	NodeSz["A"]= sizeof( A_Attrib)/ sizeof( A_Attrib[0]);
NodeSizeType	NodeSz["B"]= sizeof( B_Attrib)/ sizeof( B_Attrib[0]);

It sounds very complicate :-) Maybe someone knows a better way.

Phuoc Can HUA

On Mon, 5 Jul 2004 08:36:58 -0700, Dennis Jones <nospam@bogus.com> wrote:

> As Andrue has already said, you can do this:
>
> number of elements = sizeof( SomeStr ) / sizeof( SomeStr[0] )
>
> HOWEVER, this will only work for a static array -- that is, an array 
> whose
> size is defined at compile-time.  The only way to determine the number of
> elements in an array whose size is not static is to use a sentry value as
> the last element.  Then you iterate through the array, counting elements 
> as
> you go, and stop when you get to the sentry value.
>
> - Dennis
>
>



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