Re: AnsiString and the LineFeed char

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#6339

From: Robert G. Hoover
Date: Tue, 17 May 2005 17:20

56 lines
2365 bytes

Ok, so if I write:

MyTMemo->Lines->Text = "1\n2\n3\n4\n5";

...then I get...

1
2
3
4
5

... just as you said. But, if I write (to simulate my incoming hint)...

Application->Hint = "1\n2\n3\n4\n5";
MyTMemo->Lines->Text = GetLongHint(Application->Hint);

...I get...

1|2|3|4|

...so is my problem with the GetLongHint()?


Thanks,

Rob




Remy Lebeau (TeamB) wrote:

> "Robert G. Hoover" <not.a.real.address@anywhere.sorry> wrote in message
> news:428a086f$1@newsgroups.borland.com...
> 
> 
>>If I'm using a TMemo, then the '\n' is not interpreted as a EOL
>>char, but rather it is displayed as \n.
> 
> 
> That is not correct. "\n" is indeed treated as EOL.
> 
> 
>>For example, I'd like to send an AnsiString like the following....
>>
>>AnsiString TextString = "1. Go to start.\n2. Walk north, 3 steps.\n3.
>>Walk east, 5 steps.\n4. Dig up treasure.";
> 
> 
> That works just fine.  The \n characters are indeed treated as EOL.
> 
> 
> Gambit
> 
>

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