🚀 go-pugleaf

Just a guess but I would expect the time to be expressed as a FILETIME 
structure.  Both FILETIME and LARGE_INTEGER contain two 4 byte numbers.  Try 
using a cast to FILETIME.

.  Ed

> Ron Sawyer wrote in message
> news:451bcbac$1@newsgroups.borland.com...
>
> I am writing a custom GINA.  The portion that I am dealing with
> deals with password expiration.  The MSV1_0_INTERACTIVE_PROFILE
> has a data member that is a LARGE_INTEGER called
> PasswordMustChange.  The help file says:
>
> Time and date when the user must change the password. If the user
> can never change the password, this member is undefined. This is
> an absolute-format, Windows, standard time value.
>
> I cannot find any documentation on converting this.  Can anyone point
> me in the right direction?

From that hint it turns out to be rather simple.  For those who may want to see the solution:

CSCDate::CSCDate(LARGE_INTEGER PassedLargeInt)
{
	FILETIME LclFileTime;
	LclFileTime.dwHighDateTime = PassedLargeInt.HighPart;
	LclFileTime.dwLowDateTime = PassedLargeInt.LowPart;
	FileTimeToSystemTime(&LclFileTime, &MyTime);
}

This gives me a reasonable date (although not the one I was expecting, I now have to go check my data. I was expecting 9-29-2006 and got back 11-9-2006. Again, for those looking for this solution, if I don't post back, assume that the data matches)

I had read an article that seemed to imply (or I misunderstood) that the two dates were different.  

Thanks for the help!

"Ed Mulroy" <dont_email_me@bitbuc.ket> wrote:
>Just a guess but I would expect the time to be expressed as a FILETIME 
>structure.  Both FILETIME and LARGE_INTEGER contain two 4 byte numbers.  Try 
>using a cast to FILETIME.
>
>.  Ed
>