Re: inherited / constructors : best code ?

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#398

From: Jon Shemitz
Date: Thu, 21 Jul 2005 23:41

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OD wrote:

> > "public class B() {}" is exactly
> > equivalent to "public class B(): base() {}" 

> Ok, so c# will automatically and always call the first constructor in
> inheritance chain that will match the parameter list (that can be
> empty).

No, not quite. No initializer is the same as ": base()", but that's
it: C# will only call ": base(Foo)" if you explicitly code it that
way.

(The rule is that every class must ultimately call a base constructor.
If a constructor uses a ": this(/*whatever*/)" initializer, the other
constructor must call a base constructor, either directly or
indirectly. It doesn't matter if the 'main' constructor (that all the
others channel through) calls base directly (ie, ":
base(/*whatever*/)" or just by not having an ititializer.)

-- 

www.midnightbeach.com

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