Re: insert into problem

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#147

From: Isaac
Date: Mon, 09 Jun 2008 23:10

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Wayne Niddery (TeamB) wrote:
> update mytable set myid = myid where myid = x
>
> Locking as suggested by Bill requires the application to do two things:
> 1. Proper use of transactions
> 2. Handling the exception when the above SQL fails due to another user 
> having it locked
>
> Pseudocode would be:
>
>    start transaction // must be read committed
>    try
>        update mytable set myid = myid where myid = x
>        select max(itemnum) from mytable where myid = x
>        newitemnum := fields[itemnum] + 1
>        insert into mytable (myid, itemnum, ...) values (x, newitemnum, 
> ...)
>        commit transaction
>    except
>        // decide how to handle other user having this record locked 
> already
>        // could just go back around and try again since it should not 
> be long
>        // or can rollback transaction and inform the user to try again 
> later
>    end
>
Thanks alot, appreciate your concern

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