🚀 go-pugleaf

It depends on what the client browser does when it submits a form which
includes a file input.  Most browsers, I believe, will make a multipart
request to your server, which means you have to do more work to extract the
(binary) form data from the request.

First of all, because the browser is sending binary data, you need to get
the input stream from the request object, and then you need to decode the
bytes retrieved from this input stream.  The format for the bytes should
conform to (RFC2388) http://www.faqs.org/rfcs/rfc2388.html., which can get
quite complicated admittedly, and I have vague memories of seeing some
utility classes on the internet somewhere that will decode this information
for you.

If you simply output each byte as you read it from the stream as if the byte
read was a character, then you will see that the form data is formatted as
specified by the rfc above, and maybe the rfc will make more sense.

Also, have a look at your JSP engine (tomcat?) documentation to see if it
deals with 'multipart' form requests.

Hope this helps at least a little!
J

"Angry Orca" <luke@email.newpalm.com> wrote in message
news:3cbbece2_1@dnews...
> Hi, all:
> I encounter a problem here while I am using the jsp.
> In the client page, I use this input to post a text file to the server
side.
>
> <p><input type="file" size=40 name="file" value="*.txt"></p>
>
> On the server side, what should I do to get the content of the file?
> The tutorial says this:
> To read character data, use the BufferedReader object returned by the
> request��s getReader method. To read binary data, use the
ServletInputStream
> returned by getInputStream.
>
> But the problem is the construction of BufferedReader need another
> inputstream!! What should I do??
>
> Thanks a lot for your help.
>
> --
> ***********************
> THE TRUTH IS OUT THERE
> ***********************
>
>
>