🚀 go-pugleaf

Kevin Dean wrote:
> 
> As for distinguishing between clients, the TCP/IP protocol takes care of
> that.  It ensures that the incoming data is routed to the correct socket
> based on the source IP address and port; what you see in Java is that all
> requests from a given client will come through the same input stream.  Java
> doesn't need to do anything other than map the underlying OS API into the
> Java API.


Ok, so what if you have two separate sockets set to the same Port
Number? Let's also say, that you have different InputStream and
OutputStream type classes connected to each Socket. For instance, you're
using DataInputStream and DataOutputStream on Socket1 and
BufferedInputStream and BufferedOutputStream on Socket2.

Since we're trying to send/receive different types of data through these
sockets and they both are set to the same Port Number, is there any
chance that the incoming data can get mixed up, thereby causing
Exceptions? If there is this possibility, then perhaps it's better to
have each socket set at a different Port Number to ensure data transfer
integrity?

Regards,

Alan