🚀 go-pugleaf

Tor,

>You _need_ the package name in order to get a Class: They don't exist
>runtime without a fully qualified name.

Too true. In fact, my first attempt was:

1. Use a specific class.
2. Get the package to which it belongs.
3. Finally load the rest of the classes within this package (to ensure it's
the correct version).

I realized that Class  clss  = AClass.class; works. Because the first
specific class was a
"Factory", I had to load classes via theire name, hence the use of
Class.forName( "xxx" );

Now, if only I can remember why I made such a fuss in the first place 8-].

Thanx for your help Tor.

Hugo.


Tor Iver Wilhelmsen wrote in message ...
>"Hugo Ferreira" <HugoF@cocaina.inescn.pt> writes:
>
>> My problem is:
>> Given only the class name and not the full path via a string, how can I
get
>> the Class ?
>
>You _need_ the package name in order to get a Class: They don't exist
>runtime without a fully qualified name. Java source lets you use
>shortened names (via import) in your source, but they en up fully
>qualified in the .class file.
>
>If you do not know the package name, you cannot get the class. If you
>know _something_ about the package: For instance, "it's the same
>package as this class", then you can use the substring method and
>append ".ClassName" before calling Class.forName().