🚀 go-pugleaf

Darrel Davis wrote:
> 
> I'm a Java newbie in the middle of developing server-side code
> that transfers files to/from clients.  The clients send files and this
> method gets called.  Notice that I know the size of the file from
> the input parameters.
> 
> With this code, I seem to get the file but it is corrupted and not
> the correct number of bytes (always on the too big side).  These
> are sound files which makes it quite noticeable.  I'm sure the problem
> is simple for this group and any help is appreciated.

Accorting to the manual, DataOutputStream "lets an application write
primitive Java data types to an output stream in a portable way. An
application can then use a data input stream to read the data back in."

In other words, DataOutputString *doesn't* guarantee to write your data
as just the plain sequence of bytes you gave it.

[snip]
>       f_out = new DataOutputStream(new BufferedOutputStream (new
> FileOutputStream(sFileName)));

Try this without the DataOutputStream. And you probably shouldn't be
using DataInputStream either.

Tom