🚀 go-pugleaf

The Integer.toString() will give you a character string. This consists
of 16-bit characters. 

I'm guessing here, but it's somewhere to start...
To get 8-bit ascii characters from a string, you really should send
the string through a byte-stream writer. I think it's possible to send
to an in-memory byte-stream but I can't remember how.

I also think you might be able to take a quick and dirty short-cut
and simply cast the chars to bytes - I believe that most 'normal' 
chars have 00 in the top byte, and ASCII values in their lower bytes.

Steve
//-------------------------------------

Zhaohua Meng wrote:
> 
> Thank you much. But what I want is the 7 bits ascii character. For
> instance, in VB, Chr(12) should give me "c" and Chr(17) is "h".
> Integer.toString(17) will give me "17".
> 
> Thank you again.