🚀 go-pugleaf

I'm not quite sure what you mean by HEX value or HEX character.  I
assume you want to compare an Integer to a int constant (specified as
a hex literal).

I would do this:
if(myInt.intValue() == 0x1)
  // do something

Is this what you wanted?  Although read() returns an int, it only
reads a byte.  Do you really need to wrap the int in an Integer
object?

On Sun, 11 Apr 1999 11:08:35 -0700, "Jason C. Leach"
<leachjc@hotmail.com> wrote:

>Hi,
>
>I need a hand with the Integer class.  I am using FileInputStream and
>Output stream.  What I do is read in a byte and store it in a Integer
>object (I think):
>
>tmp = new Integer(fin.read()); //where tmp is passed into my method as a
>Integer.
>
>Then it should return after some error checking.....
>
>Now in the calling method, once that value has been fetched I need to
>check it agains a HEX value.  Here is where I get confused.  In C/C++ I
>read the byte in as a char, this is good because a byte is a char.  But
>in Java I use int, and that is 4 bytes. I don't get it.  And this causes
>more trouble as I need to compair this just read in byte of data against
>a HEX character '0x001'.
>
>Can anyone help with sorting out my confusion. And with the comparison
>syntax?
>myInteger.equals(?????); aint going to work
>
>    jason

Chris Hill
Chris244@aol.com