🚀 go-pugleaf

"Omer Azhar Qureshi" <oaq@systemeltd.com.pk> writes:

> Tor,
> i dont think that u understood the problem at hand properly,
> the Integer.parseInt (HexString, 16) method converts a hexadecimal string
> into its decimal equvalant (an int) while the problem requires that a
> Hexadecimal String be converted into its ASCII equavalant (also a
> String)....

Okay: You want to parse two and two hex digits and turn them into an
8-bit character?

int l = theString.length();
if ((l % 2) != 0)
  throw new NumberFormatException("Unbalanced hex string");
StringBuffer build = new StringBuffer();
for (int i = 0; i < l; i += 2) {
  char sixteensDigit = string.charAt(i);
  char onesDigit = string.charAt(i+1);
  char ascii = (char) (Character.digit(onesDigit, 16)
    + 16 * Character.digit(sixteensDigit, 16));
  build.append(ascii);
}
return build.toString();