Re: 0.3-0.2=0.999999999998?

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#16262

From: Stewart Smith
Date: Sat, 13 Mar 1999 00:00

43 lines
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> BTW- You can *prove* that 1 = 0.999999999(ad infinitum) as follows:
> 
> let
>   x = 0.99999999999(forever)
>
> then
>   10x = 9.99999999999(forever)
>
> now take the equation and do some math on it
>   9x = 10x - x
>   9x = 9.999999(forever) - 0.9999999(forever)
>   9x = 9
>    x = 1
>
> Thus, we have shown that
>   x = 0.9999999(forever) = 1
>
> viola!
> bobD
> --
> Roberto Diaz                                               Motorola Labs
> adb020@email.mot.com                        Application Architecture Lab
>                                                           Schaumburg, IL

But you can also do this...

let x=0.9999 (forever)
let 10x=9.99999 (forever)

and then

9x=10x-x
9x=9x
therefor x=x

0.9999999 (forever) = 0.999999 (forever)
---------------------------
Stewart Smith
Advanced God at Purple Grapefruit
web - http://vll.com/purplegrapefruit/
mail - purplegrapefruit@kagi.com
ICQ - 6734154

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From: "Stewart Smith" <stewart@SoftHome.net>
Subject: Re: 0.3-0.2=0.999999999998?
Date: 1999/03/13
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