Operator precedence

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#16355

From: MM
Date: Wed, 03 Mar 1999 00:00

40 lines
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Check this out:

<code>

public class Someclass {

    public static void main(String[] args){
        int i=0;
        int[] arr = new int[10];
        while(true){
            if(i==9) break;
            arr[i] = ++i;
            System.out.println(arr[i] + "  " + i);
        }
    }
}

</code>

The output is:

0 1
0 2
0 3
0 4
0 5
0 6
0 7
0 8
0 9

Why so?

As a side issue what it wrong with :
    ++i++;
where i is an int?

Thanks
-MM

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Subject: Operator precedence
Date: 1999/03/03
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