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Article #16357

Re: Operator precedence

#16357
From: Tor Iver Wilhelmsen
Date: Wed, 03 Mar 1999 00:00
35 lines
1254 bytes
"MM" <manu_mathew@geocities.com> writes:

> The output is:
> 
> 0 1
> 0 2
> 0 3
> 0 4
> 0 5
> 0 6
> 0 7
> 0 8
> 0 9
> 
> Why so?

Um, because you set the cell, then increment i: When it comes to the
print statement, it prints an array cell you haven't set yet, and
which has a default value of 0.

The first run of your loop is equivalent to:

arr[0] == 1;
System.out.println(arr[1] + " " + 1);

> As a side issue what it wrong with :
>     ++i++;
> where i is an int?

You cannot increment an increment expression: That is, "++i++" is
either equivalent to "(++i)++" or "++(i++)", neither of which make
sense.

Think of it: If i is 0 to begin with, the expression evaluates to
either "1++" or "++0", neither of which are legal.
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From: Tor Iver Wilhelmsen <tor.wilhelmsen@sds.no>
Subject: Re: Operator precedence
Date: 1999/03/03
Message-ID: <uogmatwur.fsf@sds.no>
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