🚀 go-pugleaf

Rob C wrote:
> String roc = "Rocker"
> 
> should read
> 
> char roc[] =  {'R', 'o', 'c', 'k', 'e', 'r'};

Actually, it probably shouldn't <g>. Unlike C, in Java a String is not an 
array of characters. Therefore, you can't call roc.substring(), because 
the array roc does not have a substring() method. (About all you can do 
with an array is gets its .length and access its elements.)

The error you got is probably due to the compiler attempting to check the 
base classes for the named method, all the way back to plain old Object.

It is perfectly legal to define an array of characters. But to print it, 
you will have to loop through the array, or copy them into a string with:

  new String( char[], int offset, int count )

which seems like cheating <g>, or any other number of ways; just not the 
way you were trying....

-- 
//Ken@Inprise
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