🚀 go-pugleaf

James,

OK, this brings up an important point (for someone new to Java like me that
is <g>).  So what you are saying is that there is no way to actually
preallocate an array of objects like you can in C++?  Even when I declare
an array of objects I MUST still allocate each object of the array
individually?  It's ALWAYS like an array of pointers?

Hmmm... if so, this can be a real performance problem when you are working
with very large arrays.  The memory management overhead of creating that
many individual objects is very slow.

Is there a way to avoid having to create all of those objects individually?

Thanks!!!

Kevin

James V. Reagan <jreagan@jpartners.com> wrote in article
<6ggepc$e11$1@Nntp1.mcs.net>...
> 
> In Java everything is a 'reference' (except for primitive types, of
course).
> References are just pointers (in fact, in C++ references are implemented
> as pointers under the hood).  You just can't do pointer arithmetic with
> references (a la C++).
> 
> So, all you would need to do is:
> 
> Object[] array1 = new Object[10000];
> Object[] array2 = new Object[100];
> 
> Object obj = new Object();
> array1[0] = obj;
> array2[0] = obj;
> 
> and voila you have your entries from two arrays referencing a single 
> object.
>