🚀 go-pugleaf

Scott wrote:

> What I'm trying to do is remove an item without using a for, or a
> loop of any kind. For example, a number of words from a hungarian
> dictionary. You are told to remove the word Szabadsag.(Some street in
> Hungary).  It won't start with the word repeat( or for or loop or any
> other similar word which is what our method does.

If you use a loop shouldn't affect what word you can or can't delete!

> //removes an item from the list public void remove(String s) { for
> (int count = 0; count < (data.length - 1); count++) { data[count] =
> data[count + 1]; } data[count + 1] = ""; }

In this version you are always deleting the first word. This fact
doesn't have to do with the fact you are using a loop but with the fact
you start at the beginning. (int count = 0;)

If you want to delete another word elswhere in your array, just start at 
this point.
f.e.:
array:
[1]  [2]  [3]  [4]
  hi   ho   hu   ha

we want to delete *hu* then we do:
for(int count = 3; count < (data.length - 1); count++) {
   data[count] = data[count + 1];
}
data[count + 1] = "";

I wrote you a code bevore where I did the following:
public void remove(String s) {
   int location = locate(s);
   for(int counter = rem_place; counter < (data.length - 1); counter++) {
     data[counter] = data[count + 1];
   }
   data[counter  1] = "";
}

You see that I get the starting point first!
(You can also write the function in various ways, one in wich you maybe 
see clearer what i am doing:)

public void remove(String s) {
   for(int counter = locate(s); counter < (data.length - 1); counter++) {
     data[counter] = data[count + 1];
   }
   data[counter + 1] = "";
}


-- 
--------------------------------------------------------------
Elrond_III      -==: Hack the World :==-
g:R->R; [a,b] in D(g) and g[a,b] in [a,b] and for all x1,x2 in [a,b]
|g(x1)-g(x2)|<=L*|x1-x2| with L <= 1 then one s in [a,b] exist with
s=g(s)
                                   -"Banachscher Fixpunktsatz"