🚀 go-pugleaf

Java always passes by reference.

However, you can only manipulate the references you have.  Within the
function call, you do not have the original reference, you have a copy of
it.  Therefore you can't change the original reference.


Simple answer is NO.






--
Peace,


Carl L. Gilbert
lamont_gilbert @ rigidsoftware.com
http://www.rigidsoftware.com
ICQ 614395-currently stolen working to retrieve.

"Then said I, Wisdom [is] better than strength: nevertheless the poor man's
wisdom [is] despised, and his words are not heard." Ecclesiastes 9:16

"wallance" <wallance@sh.ctil.com> wrote in message news:3b3bda1e_2@dnews...
> my question is can i use "PASS BY Reference" not "pass by value" in java'f
> function call?
> like in c++ ,you can use    void func(char &arg).
>
> "dnoyeB" <lamont_gilbert @ rigidsoftware.com> wrote in message
> news:3b3b7ae2_1@dnews...
> > No you can not alter objects within functions.  AS in C and C++, passing
a
> > primitive OR object into a function always copies.  If its a primitive,
> you
> > get a copied primitive, if its an object, you get a copied reference.
> > Changing the copy does not affect the original.
> >
> > That way you never have to worry about passing around your references
and
> > getting them back null.  Again, the only context a value can be set to
> null
> > is the context in which it was created.
> >
> >
> >
> > "wallance" <wallance@sh.ctil.com> wrote in message
> news:3b3b1371_2@dnews...
> > > hi,
> > > i want to change a int type argument in java,what should i do?
> > > for example:
> > >
> > > public func1(){
> > >
> > > int i = 10;
> > > func2(i);
> > > System.out.println(i)  ===> 11
> > >
> > > }
> > > public func2(int arg){
> > >     arg = arg + 1;
> > > }
> > >
> > > i know in java your can trans a object .then it can modify by
reference.
> > > but this is int type,not object.what should i do?
> > >
> > >
> >
> >
>
>