🚀 go-pugleaf

John, well that's what I meant, but of course I'am not able to express it in
a such nice english way than you did :-).

Greetings Valentino

"John McGrath [TeamB]" <ng-b@JPMcGrath.net> schrieb im Newsbeitrag
news:3af0a403$1_2@dnews...
> "Valentino Kyriakides" <vkyr@ision.net> wrote:
>
> > No, because their inner used scoping for the "String s" is different. I
> > think, thus the second ones String should been initialized first.
>
> I think I understand what you are saying, in which case, it is pretty much
> on target.  If 's' were initialized before the first 'if' statement, they
> would be equivalent.
>
> Java requires that all variables be "definitely assigned", which means
that
> the compiler must be able to verify, using relatively simple flow
analysis,
> that every variable will be assigned a value before it is used.
>
> The first example passes that test.  The variable 's' is initialized on
both
> branches of the if-then-else, so it is definitely assigned.
>
> The second example does not.  The compiler cannot examine the expressions
> (b) and (!b) and determine that one of the two must be true, so 's' is not
> definitely assigned.
>
> So the most obvious difference between the two methods is that the first
one
> will compile, but the second will get a compiler error on the return
> statement.
>
> --
> Regards,
>
> John McGrath  [TeamB]
>
>
>