🚀 go-pugleaf

Valentino,

isASCII would be simply:

  public static boolean isASCII(String s) {
    char[] chars = s.toCharArray();
    for (int i = 0; i < chars.length; i++) {
      if (chars[i] > 0xFF) { 
	return false;
      }
    }
    return true;
  }

Torsten

"Valentino Kyriakides" <vkyr@ision.net> wrote:
>Hi,
>
>the following code fragment shows a simple alphanumeric character check
>method, which checks if any char inside a passed string is alphanumeric. -
>Java's "isLetterOrDigit(char)" method's behaviour from the string class
>seems not to include whitespaces, punctuation chars like ".", the "@" sign
>and german umlauts (�������) etc.
>
>Isn't there some equivalent method available which provides something
>similar to "isASCII", which looks for all chars from ...say... the extended
>ASCII charater set or unicode set, so that all above mentioned chars will be
>recognized?
>
>.....
> // check for a string only containing alphanumeric characters
>    private boolean check_alphanumeric (String inputField)
>    {
>     char array[] = inputField.toCharArray();
>     Character chr = new Character(' ');
>     int i = 0;
>
>     while (i < inputField.length()) {
>      if (!chr.isLetterOrDigit (array[i]))
>       return false;
>      i++;
>     }
>     return true;
>    }
>....
>....
>
>Valentino
>
>