🚀 go-pugleaf

Torsten, is this character set dependend on the used locale?

I mean, if I need now only specific ranges from such an sort of extended
ASCII character set, so that I allow only specific characters ranges from
the whole [0,256], can I be shure that 0x26 till 0x2F always really include
the charcters "& � ( ) * + , - . /"?

We use the DE local and now we have for some sort of server side input
validition (shop input fields) to allow only certain alphanumeric chars, as:

 Numeric:  [0x30, 0x39]
 Range1:   [0x26, 0x2F]
 Range2:   [0x41, 0x5A]  (A-Z)
 Range3:   [0x61, 0x7A]  (a-z)
 ...
 ...

Would these always be unique independently of the the local, I don't think
so?  And what's if the local doesn't change and is always unique?


Valentino




"Torsten Welches" <torsten.welches@who.cares.netcologne.de> schrieb im
Newsbeitrag news:3acc873c$1_1@dnews...
>
> Valentino,
>
> isASCII would be simply:
>
>   public static boolean isASCII(String s) {
>     char[] chars = s.toCharArray();
>     for (int i = 0; i < chars.length; i++) {
>       if (chars[i] > 0xFF) {
> return false;
>       }
>     }
>     return true;
>   }
>
> Torsten
>
> "Valentino Kyriakides" <vkyr@ision.net> wrote:
> >Hi,
> >
> >the following code fragment shows a simple alphanumeric character check
> >method, which checks if any char inside a passed string is
alphanumeric. -
> >Java's "isLetterOrDigit(char)" method's behaviour from the string class
> >seems not to include whitespaces, punctuation chars like ".", the "@"
sign
> >and german umlauts (�������) etc.
> >
> >Isn't there some equivalent method available which provides something
> >similar to "isASCII", which looks for all chars from ...say... the
extended
> >ASCII charater set or unicode set, so that all above mentioned chars will
be
> >recognized?
> >
> >.....
> > // check for a string only containing alphanumeric characters
> >    private boolean check_alphanumeric (String inputField)
> >    {
> >     char array[] = inputField.toCharArray();
> >     Character chr = new Character(' ');
> >     int i = 0;
> >
> >     while (i < inputField.length()) {
> >      if (!chr.isLetterOrDigit (array[i]))
> >       return false;
> >      i++;
> >     }
> >     return true;
> >    }
> >....
> >....
> >
> >Valentino
> >
> >
>